1. The problem statement, all variables and given/known data An arrow is fired with a horizontal spped of 89 m/s directly at a target 60 m away. When it is fired, the arrow is 1 m above the ground. How far short of the target is it when it strikes the ground? 2. Relevant equations D = vt D = Vit + (1/2)at2 Vf = Vi + at Vf2 = Vi2 + 2ad 3. The attempt at a solution Basically my teacher says to set up a table, one side horizontal values and the other vertical values. The values I know for: Horizontal - velocity = 89, distance = 60 Vertical - acceleration = -9.8, distance = 1 Then that is where I get stuck...help? BTw the anser is 20 m short, but my teacher wants me to show work.