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## Homework Statement

A ball is kicked with initial velocity 40 m/s at an angle of 37 degree above the horizontal. What is the time (in seconds) needed to reach the maximum height?

## Homework Equations

Y-axis

h= Voy t - 0.5 g t^2

Vy= Voy - g t

Vy^2= Voy^2 - 2 g h

X-axis

d= Vox t

Vx= Vox

## The Attempt at a Solution

I reached to a point where I couldn't figure out a way to continue..

I used this equation

h= Voy t - 0.5 g t^2

h= (40 sin(37)) t - 5 t^2

I have 2 unknowns..

I tried to use Vy=Voy - g t

to find the time, I got so far these 2 equations

h= (40 sin(37)) t - 5 t^2

0=(40 sin(37)) - 10 t

Is this right?