A small mailbag is released from a helicopter that is descending steadily at 2.98 m/s. (a) After 5.00 s, what is the speed of the mailbag? (b) How far is it below the helicopter? (c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 2.98 m/s? I tried using the equation v(final)=v(initial)+gt and ended up with the wrong answer. v(final) is what i'm solving for and I plugged in 2.98 as the initial velocity, 5s for time and -9.8 for gravity. I must be using the wrong equation could I get some help?