# 2D Projectile Motion

1. Sep 9, 2012

### MattPalmer

A ball is tossed from an upper story window of a building. It has an initial velocity of 8.00 m/s at an angle of 20 degrees below the horizontal. How long does it take the ball to reach a point 10.0m below the level of launching.

I tried using the equation
yf=vi(sin(theta))-.5gt^2
Which I simplified to
(yf-vi(sin(theta)))/.5g = t^2
Then
(10-8(sin(20)))/(4.91) =t^2
Finally t=1.23, however my book says I should be getting 1.18s, what am I doing incorrectly?

2. Sep 9, 2012

### nasu

Your equation is missing a "t" in the term containing the initial velocity.
The general form should be
$$y=y_0+v_{y0}t+1/2gt^2$$

3. Sep 9, 2012

### MattPalmer

Would that mean that I need to solve the equation using the quadratic formula?

4. Sep 10, 2012

### CAF123

You are missing a 't' after the $v_o\sin\theta$ term. After you have this, rearrange your equation into the form $at^2 + bt +c = 0$ and use methods of solving quadratics.

5. Sep 10, 2012

### nasu

Yes.

6. Sep 10, 2012

### rl.bhat

Check the sign convention. If g is negative in the downward direction then yf -yo and vi*sin(theta) should be negative in the downward direction.

7. Sep 10, 2012

### MattPalmer

Got it, thanks guys