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2D Projectile Motion

  1. Feb 4, 2014 #1
    1. The problem statement, all variables and given/known data
    A basketball, thrown off a cliff with a velocity of (30.0, 25.0) m/s, lands on the ground 8.00 s later. In the absence of air resistance, what is the distance the projectile lands from the base of the cliff?


    2. Relevant equations

    http://www.ux1.eiu.edu/~cfadd/1150/03Vct2D/proj.html
    I found these equations online, but I don't know I should use them.

    3. The attempt at a solution

    viy=30 m/s
    vix=25 m/s
    t=8 s
    d=?
     
  2. jcsd
  3. Feb 5, 2014 #2

    SteamKing

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    Think about what vix and viy mean. How do they relate to the figures given in your attachment? Which one would be more helpful in calculating how far from the base of the cliff the basketball travels in 8 sec.?
     
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