Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

2nd Order DE - Power series

  1. Jul 13, 2004 #1
    After setting out in the sums and collecting the terms in [tex]x^j[/tex] I'm left with a series of expressions in
    [tex]a_2, a_3[/tex] etc as I believe i'm supposed to. However my first expression reads
    [tex]2a_{2}+2a_{1}+a_-_{1}=0[/tex]

    Now i'm told that
    [tex]y(o) = 1[/tex] and
    [tex]y'(o) = 0[/tex]
    I think this means that
    [tex]a_0 = 1[/tex]
    and
    [tex]a_1 = 0[/tex]

    does this mean that
    [tex]a_-_1 = x[/tex]?

    (My other expressions are
    [tex]6a_3+6a_2+a_0=0[/tex]
    and
    [tex]24a_4+12a_3+a_1=0[/tex])

    i'm always left with an
    [tex]a_-_1[/tex]
    when finding the other
    [tex]a_{j}[/tex]'s
     
  2. jcsd
  3. Jul 13, 2004 #2

    Dr Transport

    User Avatar
    Science Advisor
    Gold Member

    usually, negative subscript coefficients are set equal to zero initially in series solutions for differential equations.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: 2nd Order DE - Power series
  1. Solving a 2nd order DE (Replies: 11)

  2. 2nd Order De Solution (Replies: 2)

  3. 2nd order nonlinear DE (Replies: 0)

  4. 2nd order Linear DE (Replies: 1)

Loading...