Solving 2nd Order Homogeneous Equations with Non-Constant Coefficients

In summary, the conversation discusses solving 2nd order differential equations with variable coefficients, which do not have a general solution formula. The suggested methods for solving such equations include guessing the first solution and finding the second one using various methods, such as the operator method. The conversation also mentions the limitations of the undetermined coefficients method and suggests using the Frobenius method for more general linear equations with variable coefficients.
  • #1
beetle2
111
0
Hi Guys,

I know how to find the solution to a 2nd order homogeneous with constant coefficients but how do you solve one with a non constant
ie

x^2y''+2xy' ... etc = 0

Is there a general solution formula for these types of problems?

My book seems to jump from 2nd order homogeneous with constant coefficients straight to
2nd order non homogeneous with undetermined coefficients.
any help greatly appreciated.
 
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  • #2
Hello, beetle2. It didn't mentioned 2nd order with variable coefficients, since there is no general method in solving that. However, what you can do is by guessing the first solution. Then you can find the 2nd one using various method, such as:

http://www.voofie.com/content/84/solving-linear-non-homogeneous-ordinary-differential-equation-with-variable-coefficients-with-operat/"

At last, I don't really like undetermined coefficients method, which is highly restricted in the class of function you can solve. You may want to have a look at:

http://www.voofie.com/content/6/introduction-to-differential-equation-and-solving-linear-differential-equations-using-operator-metho/"

Lastly, for various tutorial, paper, articles, discussion in Ordinary differential equations, you may refer to:

http://www.voofie.com/concept/Ordinary_differential_equation/"
 
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  • #3
The specific example you give, with the coefficient of each derivative being a power of x, with power equal to the degree of the derivative, [itex]ax^2y''+ bxy+ cy= 0[/itex] is an "equi-potential" or "Euler-type" equation. "Trying" a solution of the form [itex]x^r[/itex], in the same way you "try" a solution of the form [itex]e^{rx}[/itex] for equations with constant coefficients.

That works because the substitution t= ln(x) reduces an "Euler-type" equation with independent variable x to a "constant coefficients" equation with independent variable t.

For more general linear equations with variable coefficients, you typically have to try power series solutions. Let [itex]y= \sum a_n x^n[/itex], substitute that and its derivatives into the equation and try to find the coefficients, [itex]a_n[/itex].
 
  • #5


Hello,

Thank you for your question. Solving 2nd order homogeneous equations with non-constant coefficients can be a bit more challenging than solving those with constant coefficients. However, the general approach is to use the method of undetermined coefficients or the method of variation of parameters. Both of these methods allow you to find a particular solution to the equation, which can then be combined with the general solution of the corresponding homogeneous equation to obtain the complete solution.

In the case of non-constant coefficients, the particular solution can be found by assuming a form for the solution (e.g. exponential, polynomial, trigonometric) and then substituting it into the equation to determine the coefficients. This can be a trial and error process, but it is usually more straightforward when compared to solving non-homogeneous equations.

It is also worth noting that there is no general solution formula for these types of problems. The solution will depend on the specific form of the non-constant coefficients in the equation.

I hope this helps. Please let me know if you have any further questions. Best of luck with your studies!
 

1. What is a 2nd order homogeneous equation?

A 2nd order homogeneous equation is a mathematical equation in which the highest degree of the variable is 2 and all the terms involve the variable and its derivatives. It is called "homogeneous" because all the terms have the same degree.

2. How do you solve a 2nd order homogeneous equation?

To solve a 2nd order homogeneous equation, you can use the method of undetermined coefficients or the method of variation of parameters. Both methods involve finding a particular solution and a complementary solution, and then combining them to form the general solution.

3. What is the difference between a 2nd order homogeneous and non-homogeneous equation?

A 2nd order homogeneous equation has all terms of the same degree, while a non-homogeneous equation has different degrees for its terms. Additionally, a homogeneous equation always has a trivial solution (all zeros), while a non-homogeneous equation may have non-trivial solutions.

4. Can a 2nd order homogeneous equation have complex solutions?

Yes, a 2nd order homogeneous equation can have complex solutions. This is because the coefficients and solutions of a homogeneous equation can be complex numbers, as long as they satisfy the equation.

5. What are some real-world applications of 2nd order homogeneous equations?

2nd order homogeneous equations are commonly used in physics and engineering to model systems with oscillating or vibrating motion, such as a pendulum or a spring-mass system. They can also be used to describe the behavior of electric circuits and chemical reactions.

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