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2nd order ODE

  1. Oct 15, 2006 #1
    Use reduction of order to find a second solution to the given differential equation
    (x-1)y"-xy'+y=0 x>1 y_1=e^x

    Putting it in standard form gives
    [tex] y"-x/x-1 y' + 1/x-1 y =0 [/tex]
    y'(t)= v'(t)e^x +v(t)e^x
    y"(t)= v"(t)+2v'(t)e^x +v(t)e^x
    plugging into the initial equation:
    [tex] v"(t)e^x+2v'(t)e^x+v(t)e^x-xv'(t)e^x/x-1 +xv(t)e^x/x-1 +v(t)e^x/x-1 [/tex]

    I'm not sure how to simplify this further if it can even be done, or what I should do next. Can someone please help me out?
  2. jcsd
  3. Oct 15, 2006 #2


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    Homework Helper

    Leave it in the form: (x-1)y"-xy'+y=0 x>1 y_1=e^x

    then substitute in the y, y' and y'' values for the 2nd solution.

    Simplify and you will find the v-term disappear. I just did :)
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