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## Main Question or Discussion Point

[tex]ty''-(t+1)y'+y=t^2[/tex]

I know I have to use variation of parameters to solve this.

But I am stuck and cannot figure out how to get the homologous equation!

[tex]y''-(1+\frac{1}{t})y'+\frac{1}{t}*y=t[/tex]

I don't know how to solve this homologous equation in this format.

Is it R^2+(1+1/t)R+1/t = 0 ?

How would I get my two solutions from this?

Thanks!

I know I have to use variation of parameters to solve this.

But I am stuck and cannot figure out how to get the homologous equation!

[tex]y''-(1+\frac{1}{t})y'+\frac{1}{t}*y=t[/tex]

I don't know how to solve this homologous equation in this format.

Is it R^2+(1+1/t)R+1/t = 0 ?

How would I get my two solutions from this?

Thanks!

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