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JGrecs

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## Homework Statement

each phase of a three phase delta connected generator supplies a full load current of 100A at a voltage of 240V and at a power factor of 0.6 lagging.

Find:

a) line voltage

b) line current

c) the kVA rating

d) the KW

**2. The attempt at a solution**

a) Line voltage = Phase Voltage (in delta)

VP= VL/1.732

VP= 240/1.732

VP= 138.5V

Therefore the line voltage is 138.5 volts.

b) Phase current at full load= 100A

Line current= Phase current x 1.732

IL= (100)(1.732)

IL= 173.2A

Therefore the line current is 173.2 amps.

c) kVA= (1.732)(VL)(IL)/1000

=(1.732)(240)(173.2)/1000

= 700VA

d) P= (1.732)(VL)(IL)(0.6)

= (1.732)(240)(173.2)(0.6)

= 43kW

How do these answers look? I am a little unsure of which voltages/currents to substitue into the kVA and P formulas.

Thanks,

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