each phase of a three phase delta connected generator supplies a full load current of 100A at a voltage of 240V and at a power factor of 0.6 lagging.
a) line voltage
b) line current
c) the kVA rating
d) the KW
2. The attempt at a solution
a) Line voltage = Phase Voltage (in delta)
Therefore the line voltage is 138.5 volts.
b) Phase current at full load= 100A
Line current= Phase current x 1.732
Therefore the line current is 173.2 amps.
c) kVA= (1.732)(VL)(IL)/1000
d) P= (1.732)(VL)(IL)(0.6)
How do these answers look? Im a little unsure of which voltages/currents to substitue into the kVA and P formulas.