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36 passengers in a bus

  1. Jan 10, 2013 #1
    1. The problem statement, all variables and given/known data
    Out of 36 passengers in a bus. 8 have caps, 2 have both cap and eye glasses , 26 don't have eye glasses, how many passengers have neither caps nor eye glasses

    2. Relevant equations

    3. The attempt at a solution

    A draw 2 intersected diagrams C and E. In C I write 6 dots, in the intersected point i write 2 dots, but I don't know how many should I write in Diagram E(Eyeglasses)
    The formula: C U E = C + E - CinteresectE
  2. jcsd
  3. Jan 10, 2013 #2


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    Gold Member

    You could draw venn diagrams etc.. but also consider the algebraic approach using the relation you gave at the bottom of your post. Have you come across DeMorgan's Laws?
  4. Jan 10, 2013 #3
    Perhaps you should think how many to put outside area E. You already have 6 outside that area.
  5. Jan 10, 2013 #4
    Can't make a move..
  6. Jan 10, 2013 #5


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    Gold Member

    36 passengers in a bus, 26 don't have eye glasses, so how many do?
  7. Jan 10, 2013 #6
    Okay found it, thanks.
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