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I guess to calculate the extrinsic curvature as seen from a 4D space I would just need a curvature radius, right?

Thanks

- Thread starter AWA
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- #1

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I guess to calculate the extrinsic curvature as seen from a 4D space I would just need a curvature radius, right?

Thanks

- #2

Ben Niehoff

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Then calculate the induced metric on the 3-hyperboloid. This is simply the pullback of the standard R^4 metric with respect to the embedding map.

Once you have the induced metric, you can calculate intrinsic curvature in the standard way.

Note: If you're feeling adventurous, you can take a shortcut by calculating the pullback of the R^4

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Thanks a lot for your response.

Then calculate the induced metric on the 3-hyperboloid. This is simply the pullback of the standard R^4 metric with respect to the embedding map.

Once you have the induced metric, you can calculate intrinsic curvature in the standard way.

Note: If you're feeling adventurous, you can take a shortcut by calculating the pullback of the R^4connectionto directly get the connection on the 3-hyperboloid. This would be the most efficient way to do it if you are using the Cartan formalism. But you have to remember that when you pull back connections, there is an extra term (similar to transforming a connection under coordinate transformations).

I deduce from the above that I asked something whose answer I should have supposed would be way out of my league since I didn't warn that I don't know about differential geometry.

Is there a way to explain it in plain english for someone who just have basic notions of geometry? without words like embed, connection or pullback?

I know it is not likely that it is possible but maybe somebody wanna try.

Thanks.

- #4

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In general the intrinsic curvature of a Riemannian manifold at a point isn't a single number, but in general a tensor (called the Riemann curvature tensor). It just happens that for 2D surfaces, this tensor only has one independent component, which is related to the Gaussian curvature. But for 3D manifolds, there are 6 independent components (although you can reduce this down to the Ricci tensor or further to the Ricci scalar, to get a single number. In the 2D case, the Ricci scalar is twice the Gaussian curvature.)

I suspect that you could calculate several radii of curvature to obtain the Ricci scalar. (I don't know any details.)

I suspect that you could calculate several radii of curvature to obtain the Ricci scalar. (I don't know any details.)

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