1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

3rd and 5th harmonics

  1. Feb 10, 2012 #1
    1. The problem statement, all variables and given/known data

    An a.c. voltage, V, comprises of a fundamental voltage of 100V rms at a frequency of 120Hz, a third harmonic which is 20% of the fundamental, a 5th harmonic which is 10% of the fundamental and at as phase angle of 1.2 radians lagging.

    1. Write down an expression for the voltage waveform.

    2. Determine the voltage at 20ms.


    2. Relevant equations



    3. The attempt at a solution

    Im not sure if this is right and would appreciate if someone could take a quick look over it please.

    1. I have the fundamental (Vrms x √2) at 141.4v at 120Hz
    making 3rd harmonic (20% of 141.4) = 28.3v at 360Hz
    and the 5th harmonic (10% of 141.4v) = 14.1v at 600Hz

    Therefore V=141.1 sin (2∏ft) + 28.3 sin (2∏ft) + 14.1 sin (2∏ft-1.2)

    2. Using the equation above and inserting 20ms for "t" I got the following voltages

    4.05v + -1.16v(?) + 74.15v = 77.04v

    Any help would be appreciated thanks
     
  2. jcsd
  3. Feb 12, 2012 #2

    Redbelly98

    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper

    You're pretty close. But all of your terms are at the fundamental frequency f. How can you modify the 2nd and 3rd terms, to be at the 3rd and 5th harmonic frequencies instead?
    For the first term, I get something different. Can you show more explicitly how you calculated that one term?
    I didn't calculate the 2nd and 3rd terms yet, since your original expression was incorrect. However, the 3rd term has an amplitude of just 14.1V, so no way can you get a contribution of 74.15V from it :surprised

    Hope that helps.
     
  4. Feb 13, 2012 #3
    Thanks for that

    So would it be along the lines of:

    V=141.1sin(240πt)+28.3sin(720πt)+14.1sin(1200πt-1.2)



    How im working out the voltages is using above formula, This is how I worked out first section but pretty sure im going around this the wrong way

    141.1sin = .268
    240 x π x 0.02 = 15.08

    .268 x 15.08 = 4.04v
     
  5. Feb 13, 2012 #4

    Redbelly98

    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper

    Looks good! :smile:

    To evaluate 141.1sin(240πt):
    1. Evaluate (240πt) = 240 x π x 0.02 = 15.08, as you did.
    2. Take the sine of that result, 15.08, but first be sure that your calculator is in radians (not degrees) mode.
    3. Multiply the result of Step 2 by 141.1
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: 3rd and 5th harmonics
  1. Question on Harmonics (Replies: 2)

Loading...