1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

3rd degree taylor series

  1. May 14, 2012 #1
    1. The problem statement, all variables and given/known data
    what is the 3rd degree taylor series of sin(1/10), and calculate the error of your answer.

    the wording of this question may be a little off, i just took a test and this was what i remembered about the question.

    3. The attempt at a solution
    i didnt think that this was possible because sin(1/10) is a constant, so the derivative is 0, therefor when you write out the taylor series expansion f(a)+f'(a)(x-a)/n!... is simply sin(1/10) and the error ofcourse would be 0, but im guessing im wrong because of my uncertainty.
     
  2. jcsd
  3. May 15, 2012 #2
    ##f'(a)## is telling you to evaluate ##f'(x)## at ##a##. Not to take the derivate of ##f(a)##.

    So, ##f'(1/10) = \cos{(1/10)}##

    Does that help clear it up?
     
  4. May 15, 2012 #3

    vela

    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper
    Education Advisor

    If the problem is worded as you've given it above, then your answer is correct, but it's more likely the problem was asking you to approximate sin(1/10) using a third-order Taylor polynomial.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: 3rd degree taylor series
  1. Taylor series (Replies: 14)

  2. Taylor Series (Replies: 1)

  3. Taylor Series (Replies: 2)

  4. Taylor series (Replies: 15)

Loading...