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3z-1+2√z=32This equation gets solved when we assume the z as

  1. May 4, 2012 #1
    3z-1+2√z=32
    This equation gets solved when we assume the z as any variable's2 and turn that into a quadratic form.
    Is there any other way of solving this equation?
     
    Last edited by a moderator: May 4, 2012
  2. jcsd
  3. May 4, 2012 #2
    Re: Quadratics



    Well, when we square stuff, which ammounts to basically the same thing:

    [itex]3z-33=-2\sqrt{z}\Longrightarrow 9z^2-198z+1089=4z\Longrightarrow 9z^2-202z+1089=0\Longrightarrow z_1=13.444\,,\,\,z_2=9[/itex] .

    As many times with these exercises, only the second number above is a solution to the original equation.

    DonAntonio
     
    Last edited by a moderator: May 4, 2012
  4. May 4, 2012 #3
    Re: Quadratics

    Thanks :D
    But, the assumption thing looks simple enough.
     
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