- #1
Punkyc7
- 420
- 0
Find the number of distributions of 5 distinct balls into 2 red boxes and one blue box if the two red boxes are identical and no boxes are empty.
So First I assumed that the boxes were all identical and got
5!/(3!2!)+5!/(2!2!2!) =25
from there I multiplied 25 by 2 because there are 2 different color boxes which would give me 50. The solution in the book says it should be 75 but I'm not sure why that is.
So First I assumed that the boxes were all identical and got
5!/(3!2!)+5!/(2!2!2!) =25
from there I multiplied 25 by 2 because there are 2 different color boxes which would give me 50. The solution in the book says it should be 75 but I'm not sure why that is.