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5 link chain

  1. Sep 28, 2006 #1
    umm this question seems simple enough but I don't really know what I'm doing...

    A chain consisting of 5 links, each of mass .100 kg is lifted vertically upwards with a constant acceleration of 2.50 m/s^2. Calculate the force that link 2 exerts on link 1.

    so what I did was add the masses of links 2-5 (m=0.4 kg) and multiply this by the acceleration.

    so my answer is F21 = 1 N
    I have no idea if this is even close to what I'm supposed to do.
    Help would be appreciated, thanks.
  2. jcsd
  3. Sep 29, 2006 #2


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    Staff: Mentor

    Assuming the arrangement from top to bottom is 1-2-3-4-5, and the force accelerating them upward is tied to link 1, then link 1 is pulling on the combined mass of links 2, 3, 4 and 5. So there is the weight due to gravity and the force imposed by the acceleration of 2.5 m/s2.
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