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8:1 MUX of two equations.

  1. Oct 23, 2008 #1
    1. The problem statement, all variables and given/known data
    F1 = AB + AC + BC
    F2 = (A + C’ + D’)(B + C + D)(A + B’ + C)

    2) Draw the 8-to-1 MUX implementation of F1 and F2; show your work.

    I understand doing a 4:1 of one function, but how do you do an 8:1 with two functions?
     
  2. jcsd
  3. Oct 23, 2008 #2
    put three select signals at the top: A,B,C
    F1 would take only 1,0s for each output
    and for F2, you would need some of inputs in terms of D
     
  4. Oct 23, 2008 #3
    Alright, let me try it and see. the method that I've used for 4:1 is draw the k-map (2 rows, 4 columns) and then derive the mux from that, is this a similar method? I'm assuming so and that's what I'll try again. Thanks for the quick response by the way.

    -Mikael
     
  5. Oct 24, 2008 #4
    Alright, here's what I got and I'm pretty sure it's wrong (see the note..the MUX I drew is essentially the MUX for F2, and I'm not sure about what to do with the final value relationship between F1(4) and F1(7)

    Thanks again in advance,

    -Mikael

    Edit: I should probably post a link to my work huh :-) http://img510.imageshack.us/img510/227/1331013oi1.jpg Thanks again
     
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