1. The problem statement, all variables and given/known data A 1-lb ball A is traveling horizontally at 20 ft/s when it strikes a 10-lb block B that is at rest. If the coefficient of restitution between A and B is e = 0.6, and the coefficient of kinetic friction between the plane and the block is µk = 0.4, determine the time for the block B to stop sliding. 3. The attempt at a solution M1V1=M2V2 (1/32.2)(20) + 0 = (1/32.2)(Va2) + (10/32.2)(Vb2) (Va2) + 10(Vb2) = 20 e = (Vb2-Va2)/(Va1-Vb1) 0.6 = (Vb2-Va2)/(20-0) (Vb2 - Va2) = 12 From here I get that Vb2 = 2.909 ft/s to the right Va2 = -9.091 ft/s to the left Block B T1 + U(1→2) = T2 this where I am stuck ? any help?