A 15 LB weight is dropped vertically 1 ft

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The force will be zero only if the stopping takes some nonzero time.In summary, the conversation discusses the concept of inertia and how it relates to the weight of a falling object. The question posed is about the force exerted on the ground by a 15 LB weight that is dropped vertically 1 ft and stopped instantaneously. The answer to this question is that the force would be infinite if the stopping is truly instantaneous, as per Newton's law. However, this idea of a moving object being heavier than a resting object is considered pre-scientific thinking and is not supported by Newtonian mechanics.
  • #1
Nornh
A 15 LB weight is dropped vertically 1 ft. and is stopped instantaneously. What is the weight at impact due to inertia?

That wasn't quite the answer I needed.


Question:

From "0" velocity the 15lb object is released vertically at a 1 ft drop and then it is instantaneously stopped. What is the force in lbs of the object at that point?
 
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  • #2
A 15 LB weight is dropped vertically 1 ft. and is stopped instantaneously. What is the weight at impact due to inertia?

hey,
so far i understand , you need to find the change in momentum per unit time that will give you the force i mean the weight at impact.

the initial momentum is 0 becasue initially the weight was at rest.

for the final momentum P=mv you need v to calculate.

so use the equation v^2= v0^2 + 2gh
v0= the initial velocity =0, g acceleration due to gravity and h the distance it travelled.
i hope this will help you.

bye
SKT
 
  • #3
Another way to find the speed after the weight has fallen 1 foot is to use kinetic energy. When the weight is first released, it has 0 kinetic energy and potential energy 15 pounds*1 foot= 15 foot-pounds.

After it has fallen the 1 foot, it's potential energy is 0 and it's kinetic energy is (1/2)mv2= 15. The mass of a 15 pound weight is 15/32 poundas so (15/64)v2= 15. v2= 64 and v= 8 ft/sec.

In stopping, it changes speed by -8 ft/sec (from 8 to 0).

HOWEVER! You have a serious problem- Force is "change in speed over change in time" and there is NO "change in time". You have specified that the weight is stopped "instantaneously". That can be done only by an infinite force!
 
  • #4
hi HallsofIvy


thanks, so what do you suggest then,

what should be the weight at the time of imapct? is it infinite ?
SKT
 
  • #5
I feel there is some pre-scientific thinking going on here. Children observe that a rock makes a bigger crater in the sand if it is dropped from a greater height. So they believe that a moving body is heavier than a resting body. I think this was a widely accepted concept in ancient times, too.
Newtonian mechanics claim that the larger crater is due to the larger inertial force required to stop the rock, and not due to an increased mass of the rock.
You could ask, what is the force exerted by the falling body onto the ground. But if the stopping is 'instantaneous', the answer would be an 'infinite' force via Newton's law F = ma.
 

1. What is the potential energy of the weight when it is dropped?

The potential energy of the weight can be calculated using the formula PE = mgh, where m is the mass (15 lbs), g is the acceleration due to gravity (9.8 m/s²), and h is the height (1 ft). Plugging in these values, we get a potential energy of approximately 147.15 joules.

2. What is the kinetic energy of the weight when it reaches the ground?

The kinetic energy of the weight can be calculated using the formula KE = ½mv², where m is the mass (15 lbs) and v is the velocity. Since the weight is dropped vertically, the velocity at impact will be equal to the velocity due to gravity, which is approximately 3.14 m/s. Plugging in these values, we get a kinetic energy of approximately 73.57 joules.

3. How long will it take for the weight to reach the ground?

Using the equation d = ½at², where d is the distance (1 ft), a is the acceleration due to gravity (9.8 m/s²), and t is the time, we can solve for t to find that it will take approximately 0.45 seconds for the weight to reach the ground.

4. What is the impact force of the weight when it hits the ground?

The impact force can be calculated using the formula F = ma, where m is the mass (15 lbs) and a is the acceleration due to gravity (9.8 m/s²). Plugging in these values, we get an impact force of approximately 147 N.

5. How does the height affect the impact force of the weight?

The impact force of the weight is directly proportional to the height from which it is dropped. This means that the higher the height, the greater the impact force will be. In this case, if the weight was dropped from a greater height, the impact force would be higher than 147 N.

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