team is awarded $275 in prize money and the award increases by the same amount for each successive finishing place, how much will the first place team receive? My answer : a1 -- ? D = 275 an = a1=(n-1 ) d = 275 an = a1 + ( ( 16 - 1 ) d = 8000 a1(15)(275) = 8000 a14125 = 8000 a1 = 1.93 2. Apr 23, 2010 ### HallsofIvy Re: A 16 team bowling league has$ 8,000 to be awarded as prize money. If the last pl

Does that even make sense to you? You are saying that if the last place team won $275, the first place team must have won$ 1.93!

You are told that $a_1= 275$- "If the last place team is awarded $275 in prize money" so 275 is the smallest amount in this arithmetic sequence, not the common difference. If an arithmetic sequence has initial amount $a_1$ and common difference d, then the nth number is $a_1+ (n-1)d$ and the sum is $(a_1+ (n-1)d/2)n$. You are told that $a_1= 275$, n= 16, and that the sum is 8000 so you can solve for d. 3. Apr 23, 2010 ### r-soy Re: A 16 team bowling league has$ 8,000 to be awarded as prize money. If the last pl

see I write two answer see which one is correct :

An = 2a1 + ( n - 1 ) d
a16 = 275(15) d = 80000
4125d = 80000
d = 8000/4125 = 1.9
-------------------------------
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Sn = n/2( 2.a1 ( n - 1 ) d
16/2(2(275)(15) d ) = 8000
8(8250d) = 80000
d = 8000/60000 = 0.12

4. Apr 24, 2010

### HallsofIvy

Re: A 16 team bowling league has \$ 8,000 to be awarded as prize money. If the last pl

Neither of those is correct! You have solved for d and the question does not ask for d.