A 20.0kg sled is being pulled across a horizontal surface at a constant velocity.... Hi. This is a problem on my physics homework that I can't seem to get the (correct) answer to. I would love to be told what I'm doing wrong. (: This is a problem and what I did: A 20.0kg sled is being pulled across a horizontal surface at a constant velocity. The pulling force has a magnitude of 80.0 N and is directed at an angle of 30° above the horizontal. Determine the coefficient of kinetic friction. m(sled) = 20kg F(gravity) = 20kg * 9.8 m/s2 = 196 N F(pull) = 80 N F(pull,X) = 80sin30° = 40 N F(pull,Y) = 80cos30° = 69.28 N F(normal) = 196 N - 69.28 N = 126.72 N Kinetic Friction = μ * F(normal) μ = 40 N / 126.72 N = .3157 I looked in the back in the book, and apparently the correct answer is .444. What am I doing wrong? Thanks!