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A 20 kg dog, work problem

  • #1
1. A 20.0 kg dog stands on a frictionless inclined plane. A constant upward 60.0 N force parallel to the incline is applied to the butt of the dog. As a result the dog slides upward 12.0 m along the surface. (a) What is the component of the applied force in the direction of the motion? (b) How much work is done on the dog by that force? (c) What was this work done against?



2. W=Fd



3. I know the force against it is gravity, but for the actual work i keep getting 720 J and when I look in the back of the book it's wrong. Am I using the wrong equation or just working the problem wrong altogether? W = (60 N)(12.0m) = 720 N
 
Last edited:

Answers and Replies

  • #2
798
1
Is that all the given information? What about an angle?
 
  • #3
No angle, I copied it word for word. :/
 

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