(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 8.0×10^-2 kg ice cube at 0.0 degrees C is dropped into a Styrofoam cup holding 0.35 kg of water at 12 degrees C.

A) Find the final temperature of the system. Assume the cup and the surroundings can be ignored.

B) Find the amount of ice (if any) remaining.

C) Find the initial temperature of the water that would be enough to just barely melt all of the ice.

2. Relevant equations

Q=m*C*deltaT

Q=m*Lfusion

3. The attempt at a solution

Qwater=m*C*deltaT = .35kg * 4186J/kg*k *12k = 17581.2J

Qiceto0celcius=0 because it's already at 0 celcius

Q1=Mice*Lfusion = (8*10^-2kg)*(33.5*10^4 J/kg) = 26,800J

17581.2 J - 26800J = -9218.8 J

Q2=(Mwater+Mice)*C*deltaT

-9218.8 J = (.35kg + .08kg)*4186 J/kg*k * deltaT

deltaT=-5 degrees celcius

This answer is wrong, but I'm not sure where I went wrong. Any help would be great :)

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# Homework Help: A 8.0×10^-2 kg ice cube at 0.0 degrees C is dropped into a Styrofoam cup

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