A.B = AB cos(x), and AxB = AB sin(x)

  • Thread starter newton1
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  • #1
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Main Question or Discussion Point

i know A.B = AB cos(x), and AxB = AB sin(x) ...
but if we face the problem didn't told us what should we use
then how to know what should we use
how to different scalar product or vector product.....??
 
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Answers and Replies

  • #2
HallsofIvy
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Understanding the problem might help!


It might be an important point that "AxB = AB sin(x)" is not true.
AxB is a vector whose length is the length of A times the length of B times sin(x). If you made a little more effort to distinguish between vectors and their lengths in your writing, it might help to decide whether the product in your problem was to result in a vector or a scalar!:smile:
 

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