A balanced wye delta connection

  • Thread starter mingming
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mingming
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Homework Statement


A balanced delta load having 18ohm resistance and 24 capacitive reactance in series in each phase is supplied through lines each having 1 ohm resistance and 2 ohm inductive reactance. If the line to line voltage at the sending end is 250 V, find the phase current and line currents.

Homework Equations


Zy = 1/3 Z delta


The Attempt at a Solution


i first convert the delta load to wye so the load now becomes Zy= (6-j8) and then i add the line impedance and load impedance...Zeq= (6-j8)+ (1+j2) = 7-j6 and then i solved for the line currents and phase currents which is equal for wye Ip=Il= 144.34/ 9.22 angle of -40.60
it's answer is 15.66 angle of 40.60 degrees...THIS IS WHERE I AM CONFUSED HOW DO I SOLVE THE PHASE CURRENTS AND LINE CURRENTS WHEN THE LOAD IS IN DELTA...it is not supposed to be equal since the load is in delta...please help ...
 

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