1. The problem statement, all variables and given/known data A balanced delta load having 18ohm resistance and 24 capacitive reactance in series in each phase is supplied through lines each having 1 ohm resistance and 2 ohm inductive reactance. If the line to line voltage at the sending end is 250 V, find the phase current and line currents. 2. Relevant equations Zy = 1/3 Z delta 3. The attempt at a solution i first convert the delta load to wye so the load now becomes Zy= (6-j8) and then i add the line impedance and load impedance...Zeq= (6-j8)+ (1+j2) = 7-j6 and then i solved for the line currents and phase currents which is equal for wye Ip=Il= 144.34/ 9.22 angle of -40.60 it's answer is 15.66 angle of 40.60 degrees...THIS IS WHERE I AM CONFUSED HOW DO I SOLVE THE PHASE CURRENTS AND LINE CURRENTS WHEN THE LOAD IS IN DELTA...it is not supposed to be equal since the load is in delta...please help ...