A ball is thrown horizontally from the top of a building and lands a distance d from the foot of the building after having been in the air for a time T and encountering no significant air resistance.(adsbygoogle = window.adsbygoogle || []).push({});

If the building were twice as tall, the ball would have

a) landed a distance 2d from the foot of the building

b) been in the air a time 2T

c) been in the air a time T squareroot2

d) reached the ground with twice the speed it did from the shorter building

x=x0 + v0xt + 1/2at^2

vx = v0xt +axt

and vx^2 = V0x^2 +2a (xf - xi)

Are, I think, the right equations. I don't know what to do though :(

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# Homework Help: A ball is thrown

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