What is the Work and Normal Force in a Block Pushed Up a Wall?

[Doc Al]

Since cos and 27 degrees is correct, I believe N = Fcos27. However the N force is in the negative direction. I did try N = Fcos27 in the positive direction and that answer was incorrect.

I don't see why that would be incorrect:
ΣF_x = 0
Fcos27 - N = 0
So: N = Fcos27

What value of F are you using? Be careful not to confuse force with work!

I just want to make sure that the answer has to be negative before I use any more tries.

They want the magnitude, so your answer must be positive.

 

[Warmacblu]

I don't see why that would be incorrect:
ΣF_x = 0
Fcos27 - N = 0
So: N = Fcos27

What value of F are you using? Be careful not to confuse force with work!

They want the magnitude, so your answer must be positive.

I used the value I got from the first part which is work. I guess I have to take that work and divide it by 3 to get the force?

Edit - I have to solve the force from my first equation in the y-direction. I will report back in a bit.

 

[Warmacblu]

I solved it.

I took my answer from when I solved the force for the previous part ... 104.99 and multiplied that by cos27.

Thanks for all the help with this problem, I appreciate it.

 

[Doc Al]

You already solved for the force F. Use the value you found earlier.

 

[Warmacblu]

I guess you posted a few seconds after. I managed to figure out that is the force I am supposed to use.

Thanks again.