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A bullet is fired from a gun

  1. Oct 18, 2014 #1
    1. The problem statement, all variables and given/known data
    A 0.031 kg bullet is fired from a shotgun of mass 3.63kg at 420 m/s. If the collision of the recoiling gun with your shoulder takes 0.013s, what is the average force the gun exerts against your shoulder?

    2. Relevant equations
    p = m • v

    vf=vi + at
    F=ma
    3. The attempt at a solution
    I calculated the velocity of the gun from the momentum equation : 0+0=mbf*vbf-mgf*gf
    which is 3.587 m/s
    Then I used the kinematics equation to solve for the acceleration: 3.587 m/s=0 + a (0.013 s) which is 275.9 m/s^2
    Then I used the force equation to find the force: (275.9 m/s/s) * (3.63 kg) = 1002 N. Is it right? I am worried about the acceleration because the number is high. Thanks for help.
     
  2. jcsd
  3. Oct 18, 2014 #2

    NTW

    User Avatar

    I believe you are right. The problem can be solved taking another way: the variation of momentum mv is equal to the impulse Ft

    The variation of momentum of the bullet is 13,02 m*s, and is the same as the variation of momentum of the gun.

    Thus, 13,02 = Ft

    As it's stated that the time is 0,013 s, if you solve for F, you get F = 13,02/0,013 = 1002 N
     
  4. Oct 18, 2014 #3
    Thanks!
     
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