1. The problem statement, all variables and given/known data A 0.031 kg bullet is fired from a shotgun of mass 3.63kg at 420 m/s. If the collision of the recoiling gun with your shoulder takes 0.013s, what is the average force the gun exerts against your shoulder? 2. Relevant equations p = m • v vf=vi + at F=ma 3. The attempt at a solution I calculated the velocity of the gun from the momentum equation : 0+0=mbf*vbf-mgf*gf which is 3.587 m/s Then I used the kinematics equation to solve for the acceleration: 3.587 m/s=0 + a (0.013 s) which is 275.9 m/s^2 Then I used the force equation to find the force: (275.9 m/s/s) * (3.63 kg) = 1002 N. Is it right? I am worried about the acceleration because the number is high. Thanks for help.