# A camera falling from a blimb

1. Oct 2, 2011

### joehoy41

A camera falling from a blimb.... plzzzz help

(part 1 of 2)
A camera falls from a blimp that is 349 m above the ground and rising at a speed of 17.2 m/s.
Find the maximum height reached by the camera with respect to the ground. The acceleration of gravity is 9.8 m/s^2 Answer in units of m.

(part 2 of 2)
Find the speed at which it hits the ground. Answer in units of cm/s.

2. Oct 2, 2011

### davo789

Re: A camera falling from a blimb.... plzzzz help

So which equations do you know that relate to this?

3. Oct 2, 2011

### joehoy41

Re: A camera falling from a blimb.... plzzzz help

there are a lot.. but i only want to know what does this mean "A camera falls from a blimp that is 349 m above the ground and rising at a speed of 17.2 m/s." can u give me a simple explanation of what they are saying?

4. Oct 2, 2011

### joehoy41

Re: A camera falling from a blimb.... plzzzz help

Can someone plzz help me

5. Oct 2, 2011

### DaveC426913

Re: A camera falling from a blimb.... plzzzz help

Part A of the question is improperly formed. Or it is trivial. Or you have written it out wrong.

As written, the maximum height the camera reaches is the point where it is released - 349m. Period.

Please re-examine the question you were given.

6. Oct 2, 2011

### SteamKing

Staff Emeritus
Re: A camera falling from a blimb.... plzzzz help

So, when the camera falls out of the rising blimp, its upward velocity immediately goes to zero?

7. Oct 2, 2011

### joehoy41

Re: A camera falling from a blimb.... plzzzz help

i am sure that is the question...

8. Oct 2, 2011

### DaveC426913

Re: A camera falling from a blimb.... plzzzz help

Ah, of course. My mistake. Good catch!

So the camera's params are:
Initial distance: 0m
Final distance: 349m
Initial velocity: -17.2m/s
Acceleration: +9.8m/s^2

joehoy, do you know your SAVTU equations?

9. Oct 2, 2011

### joehoy41

Re: A camera falling from a blimb.... plzzzz help

Vav = (Df - Di)/t
Aav = (Vf - Vi)/t
Vf = Vi + gt
Vf = -sqrt(Vi^2 - 2gd)
d= 0.5(Vi + Vf)t
d = Vit + 0.5gt^2
avgt = (Vf - Vi)/g
t = sqrt((2d)/g)

g = 9.81 m/s^2

10. Oct 2, 2011

### DaveC426913

Re: A camera falling from a blimb.... plzzzz help

OK. So you've got initial velocity and acceleration.

The first part of the question is only asking for the short arc of the camera as it rises to its peak.
So final velocity of that short arc is going to be what?

Which equation will give you distance, given initial v, final v and a?