# A Car going at some speed hydroplanes: does it speed up, stay the same, or slow down?

## What would the Speed of a car do when the car Hydroplanes?

• ### Slow Down

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16

#### Quarterbore

I have an on-going diasgreement and I don't wish to temper my own oppinion into this thread so I will ask the question in an open-ended way...

If you have a car going at some speed (say 55 MPH) and the car starts to hydroplane, does the car speed up, remain essentialy the same speed, or slow down?

In words, how would you prove your point?

I should add that we are making some assumptions that this is on a flat level surface and that the only change was the surface of the road from blacktop to a layer of water that caused the hydroplaning to occur.

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#### Fuego

first, think of newton's laws. for the car to speed up or slow down, the forces on it must change; there must be a net force either forwards (speeding it up) or backwards (slowing it down).

now ask the question, if the car starts hyrdoplaning, does it alter the net force on the car? yes it does, in two ways.

the first is that it decreases the friction between the car and the road. this reduces the force on the car trying to slow it down.

the second is that it effectively makes the engine less efficient. the tyres don't grip the road very well, so a lot of the engine power is wasted. this means that there is a smaller drive force pushing the car forwards.

now you need to balance these two effects: if the decrease in frictional force is greater than the decrease in drive force, the car will speed up. if the decrease in frictional force is smaller than the decrease in drice force, the car will slow down.

a simplified version of this example would be the car running in neutral (down a hill for example). if the car starts hydroplaning, the frictional force will decrease, but there is no driving force at all (only gravity). thus the car will speed up.

so the answer to your question: it depends on the specific circumstances.

#### chroot

Staff Emeritus
Gold Member
Fuego, you're making it too complicated.

To a first approximation, the hydroplaning car experiences zero friction -- this means it's not being slowed down by the road, and it's not being sped up by its tires. It's a free body.

In the absence of atmospheric drag, it'd stay the same speed as long as it hydroplaned. Of course, drag is a huge effect for cars at hydroplaning speeds, so it can't really be ignored. This drag will slow the car down, and, since there's no friction, there's nothing the tires can do about it.

- Warren

#### Chi Meson

Homework Helper
Originally posted by Fuego

the first is that it decreases the friction between the car and the road. this reduces the force on the car trying to slow it down.
When the car hydroplanes, the friction that is lost is the friction that is trying to push the car (static friction between tires and road). The friction that is trying to stop the car is primarily the air resistance, which is still present. In the real world, the car will definately slow down, but at a small rate of deceleration, and without control.

If anyone thinks it will speed up, identify the force that pushes the car forward and try to explain how this force suddenly increased when the tires lost their grip.

#### Mr. Robin Parsons

Originally posted by Chi Meson
If anyone thinks it will speed up, identify the force that pushes the car forward and try to explain how this force suddenly increased when the tires lost their grip.
When a car hits the water, the friction to force ratio that was driving the car in the first place, CHANGES, the force remains applied but now without any friction, hence the motor revs. This is followed by, under the right conditions the simplicity that the tires will (Sorta) re-attempt to establish their traction, and are now spinning at a much faster rate, so it is quite feasable that the spinning tire will, as it aquires traction, speed the car forward.

#### Chi Meson

Homework Helper
Originally posted by Mr. Robin Parsons
When a car hits the water, the friction to force ratio that was driving the car in the first place, CHANGES, the force remains applied but now without any friction, hence the motor revs. This is followed by, under the right conditions the simplicity that the tires will (Sorta) re-attempt to establish their traction, and are now spinning at a much faster rate, so it is quite feasable that the spinning tire will, as it aquires traction, speed the car forward.
But this scenario is a different problem.

As the tires initially hydroplane, the static friction between the tires and the road drops to essentially zero. At this point the two forces that were balanced (force of friction from tires and air resistance from air) are no longer balanced. Acceleration must occur in the direction of the larger force. The larger force is air resistance. THe car slows down.

Moments later the wheels will be spinning faster, and they may in fact be throwing some water backwards and so doing they will gain some forward thrust, but this will be far less than the old friction. Moments later still, the wheels will come back into contact with the surface, the car will get its frictional force back with the road, and the car will accelerate forward again, but this is after the hydroplaning is over, so its a different problem.

There might be a sensation in the real world of speeding up, but this has to do with the fact that hydroplaning occurs when we are trying to slow down. We hit a puddle, hydroplane, and then we do not slow down as fast as we were. This can feel like speeding up, but it's just slowing down less.

#### Doc

Originally posted by Mr. Robin Parsons
When a car hits the water, the friction to force ratio that was driving the car in the first place, CHANGES, the force remains applied but now without any friction, hence the motor revs. This is followed by, under the right conditions the simplicity that the tires will (Sorta) re-attempt to establish their traction, and are now spinning at a much faster rate, so it is quite feasable that the spinning tire will, as it aquires traction, speed the car forward.
Strange how you can post what I described in another thread yet you disagreed with me there.

#### turin

Homework Helper
Originally posted by Chi Meson
There might be a sensation in the real world of speeding up, but this has to do with the fact that hydroplaning occurs when we are trying to slow down. We hit a puddle, hydroplane, and then we do not slow down as fast as we were. This can feel like speeding up, but it's just slowing down less.
I think this is the main source of confusion. I've heard cops say that hydroplaning causes acceleration (as opposed to deceleration). I think the concept of acceleration is getting confused with the concept of jerk (no, not a person with a disagreeable attitude, but the third order derivative of position with respect to time).

#### Mr. Robin Parsons

Originally posted by Doc
Strange how you can post what I described in another thread yet you disagreed with me there.
That is becasue there is a circumstantalization that must be accounted for, as in what are the road conditions?, what manner of contact of water?, (rain only, large puddle, snow, ice, etc.) and what occurs in the initial timeframes?, later possible timeframes, etc.

When a driving tire hits the water, it initially hydroplanes, that loss of friction allows for the engines exerted torque to overcome what little wheel resistance is left, thus spinning the tire, that event clears some of the water from the tires track, increasing it's friction while it is now spinning at a greater speed, hence if it re-gains enough traction, it will accelerate the car, if not it won't! As stated, about road conditions, and driving wheels (front or rear or all four) all count enormously and will change the results.

Doc you were right, partially, and I did miss that one. (sorry!)

#### Chi Meson

Homework Helper
Originally posted by Mr. Robin Parsons
...spinning the tire, that event clears some of the water from the tires track, increasing it's friction while it is now spinning at a greater speed, hence if it re-gains enough traction,
WHen the wheel does re-contact the road in this scenario, the wheel surface will be skidding against the road surface. THis means the friction that returns to propel the car will be of the kinetic form. We want static friciton to propel the car (the kind when the wheels aren't skidding). Kinetic friction is never greater that static friction, so there is no way under normal conditions that a greater force will be applied to the road. The wheels will not "grab" the road until the tangential speed of the wheel's surface is equal to the speed of the car (whic has now slowed down). Once the wheels re-establish static friction, the car will again accelerate positively, but it has already slowed by this time.

#### Mr. Robin Parsons

Originally posted by Chi Meson
WHen the wheel does re-contact the road in this scenario, the wheel surface will be skidding against the road surface. THis means the friction that returns to propel the car will be of the kinetic form. We want static friciton to propel the car (the kind when the wheels aren't skidding). Kinetic friction is never greater that static friction, so there is no way under normal conditions that a greater force will be applied to the road. The wheels will not "grab" the road until the tangential speed of the wheel's surface is equal to the speed of the car (whic has now slowed down). Once the wheels re-establish static friction, the car will again accelerate positively, but it has already slowed by this time.
applies to the reddened part How do you establish that it has "now slowed down" when the engines speed has NOT been backed off of, (it actually increased due to the loss of traction/resistance) and the wheels are still having the same, or greater, amount of torque being applied to them by that motor?

#### Chi Meson

Homework Helper
No matter what the engine does, and no matter how much torque is produced, the car will have no forward propulsion force unless the wheel are contacting the ground. The maximum force that that car can apply to the road is equal to the maximum static frictional force between the road and the tires.

Take your car on to very slick ice. Same car, same engine, same "torque," but very little forward force because the static friction is near zero. This is also why your car cannot work when its wheels are off the ground.

If you are driving along with the accelerator to the floor and the ground drops away from you, can you imagine a situation where you would speed up? (In the forward direction I mean, of course you would start to fall down and speed up that way).

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#### Mr. Robin Parsons

Originally posted by Chi Meson
No matter what the engine does, and no matter how much torque is produced, the car will have no forward propulsion force unless the wheel are contacting the ground. The maximum force that that car can apply to the road is equal to the maximum static frictional force between the road and the tires.
Take your car on to very slick ice. Same car, same engine, same "torque," but very little forward force because the static friction is near zero. This is also why your car cannot work when its wheels are off the ground.
If you are driving along with the accelerator to the floor and the ground drops away from you, can you imagine a situation where you would speed up? (In the forward direction I mean, of course you would start to fall down and speed up that way).
You seem to be dealing with this as a static surface, it isn't it is a tire tread on/in water, the rotational speed of the tire increasing, will cause the removal of more of the water from underneath the tire's tread, hence it will begin to re-establish traction coefficients at a higher rate of rotation, thus speeding the vehicule forward.......Doc's right for the circumstance(s)..........

#### Chi Meson

Homework Helper
You need to brush up on the forces of friction. Traction coefficients is a term I am not familiar with. You you mean coefficients of friction? In Doc's earlier post he used the term "friciton to force ratio" : this sounds like the coefficient of friction to me, but that is the "frictional force to weight ratio," nothing to do with the force or torque of the engine.

As for thinking it is a static situation, you need to reread my post. It is specifically the loss of the static situation that causes a sudden loss of propulsion force.

If a tire is spinning on the surface of anything, it is a kinetic friction situation. If and when the car reestablishes contact with the surface of the road, the kinetic friction will be the same no matter what rate the wheel is spinning (assuming that the temperature of the rubber is not changing). Kinetic friction does not depend on the relative speeds of the two surfaces.

Doc is not right on this one. Newton is. Sorry.

#### Mr. Robin Parsons

Originally posted by Chi Meson
You need to brush up on the forces of friction. Traction coefficients is a term I am not familiar with. You you mean coefficients of friction? In Doc's earlier post he used the term "friciton to force ratio" : this sounds like the coefficient of friction to me, but that is the "frictional force to weight ratio," nothing to do with the force or torque of the engine.

As for thinking it is a static situation, you need to reread my post. It is specifically the loss of the static situation that causes a sudden loss of propulsion force.

If a tire is spinning on the surface of anything, it is a kinetic friction situation. If and when the car reestablishes contact with the surface of the road, the kinetic friction will be the same no matter what rate the wheel is spinning (assuming that the temperature of the rubber is not changing). Kinetic friction does not depend on the relative speeds of the two surfaces.

Doc is not right on this one. Newton is. Sorry.
I have a suspicion that you think that the wheel re-engages at a fixed contact pressure, it doesn't, it's re-conection with the road surface (traction/friction) is an even unto it'self inasmuch as the tire and the road surface will gain in friction/resistance relatively quantified upon the amount of water V expulsion of that water, the amount of pressure upon that wheel, at that time, relative to the inertial mass distribution over time, the "backwash trail" it might be following, (for rear wheel drives) or slips out of, the braking resistive forces, acting on the front end of the car, that may steer, and decelerate the front end, such that re-establishing simply the preset road speed might seem "The Acceleration" from the deceleration that occured upon entry to the hydroplaning event site, etc. etc.

#### Chi Meson

Homework Helper
I could not understand your last post.

This is the last post for me in this thread. After this, I’ll just be spinning my wheels. In the macroscopic world, Newtonian mechanics is valid. Quantum theory does allow for small, but non-zero possibilities for almost anything to happen, so ignoring all quantum fluctuations, we must examine forces.

What are all the forces that act on the car (internal forces cannot act on the car; see Newton’s first law)? The static frictional force of the road on the car’s tire (this is the reaction to the force of the car’s tires on the road; see Newton’s third law) , the resistance of the air (this is a function of the car’s relative speed with the air), and the resistance of the water in the puddle as the car enters the puddle.

There is one significant downward force on the car, its weight. The supporting force on the car from the ground or (whatever is underneath it) is the "normal force." These forces are balanced when the car is ona flat surface.

Only one of these forces is in the forward direction, the static friction. While traveling at a constant speed this force is balanced by the resistance force. When the car hydroplanes, the static friction is lost (because "mu" goes to nearly zero) . Within this instant, there is no significant forward force (If the tires regain contact with the road, then the car is no longer hydroplaning).

Now the car is hydroplaning; its wheels are spinning, throwing water behind it. The forces that are trying to slow the car down are: the resistance of the air and the resistance of the water in the puddle. The only force that is trying to push the car forward might be a small reaction force to the car throwing the water backward.

So the net forward propulsion force has dropped nearly to zero, while the resistant forces probably have actually increased. If the negative forces are more than the positive forces, then acceleration will be in the negative direction (see Newton’s second law).

That is all there is to it. The car slows down.

#### Doc

Ok Chi, get your sh!t together before you quote me. Parsons and I had an argument in a totally separate thread concerning cruise controls. I have never said anything about friction to force or whatever.

Here is the scenario:

#### Chi Meson

Homework Helper
Doc:

Since you are getting insulting, I have to break my word on not continuing on this thread. I did make a mistake. It was Mr. Parsons who used the term "friction to force ratio." I accidentally attributed to you. As for your analysis of the situation, I will say, for the third time, that when the tire reengages contact with the road, it is no longer hydroplaning.

And again, when the wheels are spinning faster than the road, the friction upon contact will be the slipping sort of friction which is less force than the static kind. Upon contact, will the car again accelerate? Sure. But the car must already have slowed down. Not enough time you say. Well let's agree that if there is enough time for a wheel to increase its rotation, there is enough time for the car to slow down.

Even if it only a few microseconds, while the car is hydroplning, the car is slowing down.

And BTW. the bit about "think that they know something about physics"? I really believe Newton is right.

#### Doc

Originally posted by Chi Meson
Doc:

As for your analysis of the situation, I will say, for the third time, that when the tire reengages contact with the road, it is no longer hydroplaning.

Yeah, you've said it. Why do you insist I am wrong? I FLAT OUT F***ING SAID that when the wheels come off of the ground the car will slow down. AM I WRONG?!?!?!?!

Originally posted by Chi Meson

And again, when the wheels are spinning faster than the road, the friction upon contact will be the slipping sort of friction which is less force than the static kind. Upon contact, will the car again accelerate? Sure. But the car must already have slowed down. Not enough time you say. Well let's agree that if there is enough time for a wheel to increase its rotation, there is enough time for the car to slow down.

Chi is talking to the cop after hydroplaning, losing control, and slamming into another vehicle. You argue that it WASN'T really the hydroplaning (which a sign 1/4 mile back warned of) that caused the wreck. It was that darn re-entry onto the pavement. Heck if I could have just 'surfed' all the way down that next traffic light I would have been fine.

Originally posted by Chi Meson

Even if it only a few microseconds, while the car is hydroplning, the car is slowing down.

Yeah, I already covered this earlier in this post.

Originally posted by Chi Meson

And BTW. the bit about "think that they know something about physics"? I really believe Newton is right.
I actually covered this in the last post. When did I say Newton was wrong? I just said you haven't seen the light. And I also said:
We have a bunch of people that are on the road who think they know everything about driving because they know, or at least think that they know something about physics?
I NEVER said specifically that you 'thought you knew'. I included both. You CHOSE ON YOUR OWN to 'think that you knew'.

Wanna keep going? You seem to keep arguing (at least with me) just for the sake of argument. Oh, I know. You wanted the last word after I told you to get your stuff together. I really think we are on the same wavelength. You just refuse to see it.

You might want to think twice about that experiment out on the highway though, I might see it and add it to my mental list of idiot drivers. Nah, just kidd'n.

#### Chi Meson

Homework Helper
Doc,
Please please calm down. My arguments were with Mr Parsons and not with you. I did get one of the earlier posts confused, and I mistook the "stuff together" post as a refutal of my previous post. This is clearly not the case, and I am sorry for the confusion. Your prior post was insulting to me though, veiled or not.

So let's both drop this thread, it's going nowhere and someone might succumb to road rage. See you elsewhere, peace.

[edited to fix syntax]

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#### Doc

But I wanna hear about your experiment. Believe me, if I see anything like what I described I will assume it is you. You never said anything about being a teenager and tearing up the roads either. I assumed you didn't. Now's your chance. LOL BTW, I got a little p!ssed because it seemed like it was implied that I said some things I didn't. If you want to get under my skin, twist my words around into something they aren't. I choose words carefully to avoid sounding like an idiot and to avoid being misunderstood. I am quite aware that sometimes the words I choose cause me to sound other ways though. It's my choosing. You can tell me to calm down but I probably already have.

Oh yeah, one last thing. I think Parsons feels the exact same way I do about the argument. Don't want to say that for 100% though because I don't like it when people do that to me. I think he realizes that it is impossible for the vehicle to speed up when the wheels come off of the ground.

#### Chi Meson

Homework Helper
How could I tear up the road with a Volvo?

#### Doc

Originally posted by Chi Meson
How could I tear up the road with a Volvo?
I'll bet some of my friends and I could have found a way to do it back in the day. LOL

Homework Helper
Last word.

#### beluluk

seems that i'm just too late to get in the discussion, but since i really wish to post my opinion... well... you know .

When the car hydroplanes, i think, it will got such resistance that the speed decreases, and the acceleration either. It would be somewhat like a beam is biassed from air to water. So..., my conclusion is "we are discussing about speed", and even we are disscussing the acceleration, i think that it will also decreased. well... to say it is damped is more likely i think.

well..., after typing that, it just got to me...: "am i sure that hydroplaning is going underwater?" well i'm not sure... but i just post this anyway.

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