# Homework Help: A cart with a block on it

1. Nov 14, 2007

Hey guys, I'm struggling a little bit with this physics problem (look at the attachment for a diagram of the situation about to outline).

There is a cart, upon which a block of a material of uniform density, with width w and height h rests. The coefficient of friction between the block and the cart is enough so that when the cart begins to accelerate, the block cannot slide, but instead topples over.

At what acceleration will the block topple? I need to find a general solution for this situation.

These are the forces I can identify:

a) the weight of the block, mg (acting through the center of mass, which lays in the geometric center of the object, since it is of uniform density)
b) the normal force to the weight of the block (acting through the center of mass, in the direction opposite to that of mg)
c) the force of friction between the block and cart (this is the force that is accelerating the cart, and it acts along the surface of the block)

The problem is, I can't figure out which force causes the counterclockwise torque that causes the block to topple over, and I know for a fact it's not one of the above three forces. I know it's a counterclockwise torque because I did some modelling using a sheet of paper and an eraser, which acted as my block). Our teacher says that the force responsible for the torque would be the "pseudo force", ma, which acts in the direction parallel to the acceleration, a, and through the center of mass.

That doesn't make sense either, because that force, ma, would cause a torque in the clockwise direction, not counterclockwise.

WTH is happening?

Also, I learnt that any force going through the center of mass of an object, cannot create a torque. Why then, do we use mg (the weight of an object), in torque analyses often times?

Your help is greatly appreciated. :)

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• ###### physicsprob.gif
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Last edited: Nov 14, 2007
2. Nov 14, 2007

### cesiumfrog

The easiest way to solve this problem is to recognise that being on an accelerating cart is equivalent to being stationary in a room where the force of gravity is slightly different (in direction and magnitude, though it's the former that determines whether an object is balanced).

If that's conceptually problematic, note that just before the "topple" the normal and frictional forces will act on the corner (not through the c.o.m.).

3. Nov 14, 2007