A charged cork ball is suspended on a light string in the presence of a uniform electric field.
E=(3×10^5 N/C)i+(5×10^5 N/C)j. The ball is in equilibrium in the field.
Find the charge on the ball. The acceleration due to gravity is 9.8 m/s2 . The mass of the ball is 0.7g. The length of the string is 1.4m and at an angle of 37 degrees from the center.
Answer in units of nC.
Also find the tension of the string.
The Attempt at a Solution
Will someone please let me know if my solution and answer is correct?
(3*10^5)q*cot(37) + (5*10^5)q = .00686
Solve for q and q=7.6382nC
T=(3*10^5)q/sin(37) plug in q and T=.003808N
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