# A charged cork ball is suspended on a light string in the presence of a uniform electric field

## Homework Statement

A charged cork ball is suspended on a light string in the presence of a uniform electric field.
E=(3×10^5 N/C)i+(5×10^5 N/C)j. The ball is in equilibrium in the field.
Find the charge on the ball. The acceleration due to gravity is 9.8 m/s2 . The mass of the ball is 0.7g. The length of the string is 1.4m and at an angle of 37 degrees from the center.

Also find the tension of the string.

## Homework Equations

Tsin(theta)=FEx
Tcos(theta)+FEy=mg
F=Eq

## The Attempt at a Solution

Will someone please let me know if my solution and answer is correct?

Tsin(37)=(3*10^5)q
Tcos(37)+(5*10^5)q=(.0007)(9.8)
T=(3*10^5)q/sin(37)
(3*10^5)q*cot(37) + (5*10^5)q = .00686
Solve for q and q=7.6382nC

T=(3*10^5)q/sin(37) plug in q and T=.003808N

Last edited by a moderator:

gneill
Mentor
It looks good. You might have put in some comments regarding what you were accomplishing or doing at each step in order to make your thought process clear. Otherwise, very well done!

@gneill Thanks! I will definitely do so next time :)

haruspex