1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

A circular motion problem

  1. Nov 13, 2011 #1
    1. The problem statement, all variables and given/known data
    In an amusement park ride, people are spun at 5 radians per sec in a 3 m cylinder. What is the coefficient of friction to prevent people from falling down?


    2. Relevant equations
    Centripetal Force= (mv^2)/r
    Force of friction=(mu)(mg)
    Velocity=(r)(ω)

    3. The attempt at a solution
    V=(3 m)(5 rad/sec)=15 m/s
    Centripetal Force=(M(15^2))/3=75M
    Centripetal force=force of friction...
    75M=9.8(mu)M
    75/9.8=(mu)=7.653?
     
  2. jcsd
  3. Nov 13, 2011 #2
    No need to answer. I get this now....
     
  4. Nov 13, 2011 #3

    Delphi51

    User Avatar
    Homework Helper

    Is it a vertical cylinder of radius 3 m? (A 3m cylinder suggests the diameter is 3.)
    With the people above the floor of the cylinder?
    If so, the centripetal force is the normal force, not the force of friction.
     
  5. Nov 13, 2011 #4
    yea that was my mistake...
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: A circular motion problem
  1. Circular motion problem (Replies: 10)

Loading...