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Forums
Mathematics
Differential Geometry
A claim about smooth maps between smooth manifolds
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[QUOTE="martinbn, post: 6866150, member: 252793"] For the first part, the only thing is that the open set ##U##, which is the domain of the smooth function, need not be a chart. Same for its inverse image. So you need to take smaller open subsets around any point in ##U##. For the second part. The standad way is to consider charts and pull back the coordinate functions. Since they are smooth, the map will be a smooth map. [/QUOTE]
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Mathematics
Differential Geometry
A claim about smooth maps between smooth manifolds
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