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A complex complex root

  1. Sep 20, 2007 #1
    G'' = -kG
    k is a constant
    solving this ODE, r = +/- sqrt(-k)
    if k > 0, then r = +/- sqrt(k)i
    so G is in the form Acos(sqrt(k)x) + Bsin(sqrt(k)x)

    so, what if k is a complex number, then
    r = +/- sqrt(-ki)

    then what is the form of G?
  2. jcsd
  3. Sep 20, 2007 #2
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