• Support PF! Buy your school textbooks, materials and every day products Here!

A complex complex root

  • Thread starter madeinmsia
  • Start date
  • #1
15
0
G'' = -kG
k is a constant
solving this ODE, r = +/- sqrt(-k)
if k > 0, then r = +/- sqrt(k)i
so G is in the form Acos(sqrt(k)x) + Bsin(sqrt(k)x)

so, what if k is a complex number, then
r = +/- sqrt(-ki)

then what is the form of G?
 

Answers and Replies

Related Threads on A complex complex root

  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
8
Views
1K
  • Last Post
Replies
5
Views
1K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
20
Views
2K
Replies
3
Views
2K
  • Last Post
Replies
4
Views
930
  • Last Post
Replies
4
Views
466
Replies
3
Views
2K
Top