- #1
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G'' = -kG
k is a constant
solving this ODE, r = +/- sqrt(-k)
if k > 0, then r = +/- sqrt(k)i
so G is in the form Acos(sqrt(k)x) + Bsin(sqrt(k)x)
so, what if k is a complex number, then
r = +/- sqrt(-ki)
then what is the form of G?
k is a constant
solving this ODE, r = +/- sqrt(-k)
if k > 0, then r = +/- sqrt(k)i
so G is in the form Acos(sqrt(k)x) + Bsin(sqrt(k)x)
so, what if k is a complex number, then
r = +/- sqrt(-ki)
then what is the form of G?