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Kc1 = (5.8*2/5)^2 / (14/5)(1.4/5) = 6.865

6.865 = [HI]^2 / (45/253.8/100)(0.5/2/100)

[HI] = 5.52x10^-3 M

mass no of HI = [HI] x (126.9+1) x 100 = 70.6g

is it correct?

And how to do 3bii

I GOT 3bi Kc2 = [HCl(g)]^2/ / Kc(1) [H2(g)] [Cl2(g)]

6.865 = [HI]^2 / (45/253.8/100)(0.5/2/100)

[HI] = 5.52x10^-3 M

mass no of HI = [HI] x (126.9+1) x 100 = 70.6g

is it correct?

And how to do 3bii

I GOT 3bi Kc2 = [HCl(g)]^2/ / Kc(1) [H2(g)] [Cl2(g)]