# A constant without name?

## Main Question or Discussion Point

Hi,

I was wondering if the constant
$$\sum_{n=1}^\infty{2^{-2^n}}$$

has a certain name or some history or anything. It certainly appears not to have a closed form expression. It also certainly has some value because it's majorized by the simple geometric series. It's numerical value is 0.31642150902189314371 (given by http://www.research.att.com/~njas/sequences/A078585" [Broken], but is there anything else known about it?

Regards,

Pere

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disregardthat
Hi,

I was wondering if the constant
$$\sum_{n=1}^\infty{2^{-2^n}}$$

has a certain name or some history or anything. It certainly appears not to have a closed form expression. It also certainly has some value because it's majorized by the simple geometric series. It's numerical value is 0.31642150902189314371 (given by http://www.research.att.com/~njas/sequences/A078585" [Broken], but is there anything else known about it?

Regards,

Pere
It's transcendental, if I'm not mistaken.
$$|\sum_{n=1}^\infty{2^{-2^n}}- \sum_{n=1}^k{2^{-2^n}}| = |\sum_{n=k+1}^\infty{2^{-2^n}}| = |\sum_{n=1}^\infty{2^{-2^n2^k}}| \leq |\sum_{n=1}^\infty{2^{-2^n}}|^{2^k} < \left(\frac{1}{2}\right)^{2^k}=\frac{1}{2^{2^{k+1}}}$$

The denominator of the rational number $$\sum_{n=1}^k{2^{-2^n}}$$ is $$2^{2^k}$$. The number is thus a liouville number, and therefore transcendental.

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