- #1

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f(X)= x^3 + 3x^2-24x

f'(X)= 3x^2 + 6x -24

what do i do, next i found the derivative of the function

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- Thread starter afcwestwarrior
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- #1

- 457

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f(X)= x^3 + 3x^2-24x

f'(X)= 3x^2 + 6x -24

what do i do, next i found the derivative of the function

- #2

arildno

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- #3

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so i just plug in any numbers in the x's

- #4

arildno

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so i just plug in any numbers in the x's

Eeh??

Do you know what an equation is, and how to solve it??

- #5

- 457

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i think ido, can u show me an example

- #6

- 457

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yes i know what an equation is, but how do i solve it

- #7

hage567

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Can you name what type of equation that is?

- #8

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- #9

hage567

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Just look at its form. It's a QUADRATIC equation! Have you not learned about those before? There's a formula for finding the roots of a quadratic equation. If you don't know it, look it up.

- #10

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ok, so when i take the derivative, i just factor it out

- #11

hage567

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ok, so when i take the derivative, i just factor it out

What?? I don't understand what you mean by that.

- #12

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well when i factored it out, i got 3(x^2+2x-8) then i factored it out

3(x+2)(x-4) ok thats easy, i forgot about that algebra stuff and trig and geo, like my calculus teacher said, it's not the calculus its all that old stuff that will get ya

- #13

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i mean 3 (x-2) (x+4)

- #14

hage567

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i mean 3 (x-2) (x+4)

OK that's better I was just going to point that mistake out.

- #15

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yea hey thanks for reminding me about that,

- #16

hage567

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