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A cube of ice's mass

  1. Jul 11, 2014 #1
    A cube of ice is taken from the freezer at -8.5C and placed in a 95g aluminium calorimeter filled with 310g of water st room temperature of 20C. The final situation is observed to be all water at 17C. What was the mass of the ice cube?

    C (al)= 900, C (water)= 4186, C (ice)= 2100

    m(al)= 0.095kg, m(water) = 0.310kg, m (ice)= ??
    T (ice)= -8.5 C,T(final)= 17C, Twater= 20C, I assume the temperature of the aluminium container is the same of the water at 20C so T(al)= 20C,

    heat lost= heat gained

    I got --> m(al)C(al){ Tal- Tf} + m(w) C(w) { Tw- Tf) = m(ice) C(ice) { Tf- Ti}.
    And then of course I would derive the formula to find the missing m(ice). However I am not getting the right answer. Can someone show tell me what I neeed to change in the formula?
     
  2. jcsd
  3. Jul 11, 2014 #2

    NascentOxygen

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    Staff: Mentor

    Did you take into account the latent heat of the solid ←→ liquid phase change?
     
  4. Jul 11, 2014 #3
    Oh, I forgot that, umm.. so I would add m(w) Lfusion on the left side and m(ice) Lfusion on the right ??
     
  5. Jul 11, 2014 #4

    NascentOxygen

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    Staff: Mentor

    Not both sides, just one. It melts, and stays melted.
     
  6. Jul 11, 2014 #5
    oh right I was thinking I needed it for the water, but it doesnt change state, SO + m(ice) Lfusion on the right side? Is the rest of my equation right?
     
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