- #1
lttlbbygurl
- 6
- 0
So I came across this problem in my textbook, but couldn't seem to solve it...
Let n be any squarefree integer (product of distinct primes). Let d
and e be positive integers such that de — 1 is divisible by p — 1 for every prime divisor p of n. (For example, this is the case if [tex] de \equiv 1 mod \phi(n) [/tex].) Prove that
[tex] a^{de} \equiv a mod n [/tex] for any integer a (whether or not it has a common factor with n).
Let n be any squarefree integer (product of distinct primes). Let d
and e be positive integers such that de — 1 is divisible by p — 1 for every prime divisor p of n. (For example, this is the case if [tex] de \equiv 1 mod \phi(n) [/tex].) Prove that
[tex] a^{de} \equiv a mod n [/tex] for any integer a (whether or not it has a common factor with n).
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