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A difficult integral?

  1. Nov 24, 2009 #1
    Hi all,
    Can you guys please help me with the following integration problem

    ∫ [x (8-x3)^1/3 ] dx
    Thanks in advance.
    Last edited: Nov 24, 2009
  2. jcsd
  3. Nov 24, 2009 #2


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    Gold Member

    What have you attempted for the problem so far?
  4. Nov 24, 2009 #3
    I have substituted u^3 = 8 - x^3 then 3 u^2 du = - 3 x^2 dx
    But now the problem has only x so in order to substitute for dx I have to divide and multiply by x and that means I can not eliminate cube root.
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