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**[SOLVED] A falling man**

## Homework Statement

a 90kg man falls (freefalls) 10m, when he lands, his legs buckle and he goes down another 23cm. What was the average force he exerted on the ground?

## Homework Equations

M = 90k

a = 9.8 m/s^2

## The Attempt at a Solution

from freefall to ground

F(g) = 90kg (9.8m/s^2)

F(g) = 882N

buckling

F(g) = 90kg (9.8m/s^2)

F(g) = 882

(882 + 882)/2 = 882

average force = 882?

Im confused, does the distance have anything to do with the question? Because F = ma, so as long as its accelerating but the distance does not matter.

but this seems a bit too easy, so im pretty sure i did something wrong =/