What is the Maximum Velocity of a Person Falling from a 35 Meter Tower?

In summary, DaveC426913 and Integral helped a new user with homework. DaveC426913 told the user that they needed to use their kinematic equations to solve for the speed and displacement of the object after it falls from a height. Additionally, the user was told that the mass of the object does not matter, and that any falling object will have the same speed.
  • #1
phuketman
3
0

Homework Statement



A 69 kilogram person falls from a 35 meter tower head first to the ground

Homework Equations



What is the maximum velicoity he reaches before impact?

The Attempt at a Solution

 
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  • #2
See that #3? That's where you make an attempt at a solution.

We don't spoon-feed homework here.
 
  • #3
Hint: Use your kinematic equations for uniform acceleration.
 
  • #4
Sorry if I am a dumbum. I'm 57 and have forgotten all my equations, not that I was very good at physics. I am doing research for a stuntman who has survived this fall and want to know what speed he reached.
 
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  • #5
The https://www.physicsforums.com/showthread.php?t=5374" that you agreed to when you signed up require you to attempt a solution:

"NOTE: You MUST show that you have attempted to answer your question in order to receive help."


Furthermore, we are expressly requested not to do work for people here; this is afterall, and homework help forum.
 
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  • #6
V = Vo + at
X - Xo = Vot + .5at2
v2 = vo2 + 2a(X - Xo)
X - Xo = .5(Vo + V)t

V is final velocity in units of meters per seconds (m/s)
Vo is initial velocity in units of meters per seconds (m/s)
a is acceleration in units of meters per squared seconds (m/s2)
t is time in seconds (s)
X is final displacement in units of meters (m)
Xo is initial displacement in units of meters (m)
 
  • #7
The mass does not matter, any falling object will have the same speed after falling 35m.

First you need the time of the fall.

x = fall distance = 35m
a = acceleration due to gravity = 9.8 m/s
t = time of fall.

x = .5 a t^2
[tex] t = \sqrt { \frac {2x} a } [/tex]

Given the time of the fall the speed is

v = at

so [tex] v = \sqrt {2 a x} [/tex]

That should give you all the equations you need. can you take it from here?
 
  • #8
thank you DaveC426913 and Integral. I am new to this board and appreciate your help.
I will not bother you again.
 
  • #9
phuketman said:
thank you DaveC426913 and Integral. I am new to this board and appreciate your help.
I will not bother you again.

Feel free to bother. That's what we're here for. :wink: But there's rules is all.
 

What is the formula for calculating the speed of a falling object?

The formula for calculating the speed of a falling object is v = gt, where v represents speed in meters per second, g represents the acceleration due to gravity (9.8 m/s²), and t represents time in seconds.

How does the mass of a falling object affect its speed?

The mass of a falling object does not affect its speed. All objects, regardless of their mass, will accelerate towards the ground at the same rate due to gravity.

What factors can influence the speed of a falling object?

Aside from the acceleration due to gravity, the speed of a falling object can also be influenced by air resistance, the shape and size of the object, and the height from which it is dropped.

Why does the speed of a falling object increase as it falls?

The speed of a falling object increases as it falls because it is being pulled towards the ground by the force of gravity. As the object falls, it gains momentum and its speed increases until it reaches its terminal velocity.

Can a falling object ever reach a constant speed?

Yes, a falling object can reach a constant speed known as its terminal velocity. This is the maximum speed an object can reach due to the balance between the force of gravity and air resistance.

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