# A Few Question On Lens and Magnification

1. Apr 27, 2009

### shimizua

1. The problem statement, all variables and given/known data
So i thought it was Real, magnified, and inverted but just wanted to check. Then also i wanted to know this
here is the picture http://www.gatewaytosedona.com/image/articles4/2121/EST_Jupiter_416w.jpg [Broken]

Look up the size of Jupiter and the distance to Jupiter
when it is closest to Earth. Use the lens formula to
determine the magnification of the image. How many
pixels in diameter is Jupiter’s image on the CCD? How
large a square on the surface of Jupiter does one pixel in
the image represent?

so the size of jupiter is 1.9x10^27 kg
distance is 591 million km
and the diameter of jupiter is 143,000,000 m
and the diameter of the image is .034 m

so to find the magnification i did m=hi/ho and go 2.38x10^-10, but i just didnt think it shouldbe so small since i thought it was magnified. but if i am wrong with the first part then that could be right
So then for the next with how man pixels, it would just be 1024 pixels right?
Then the last part would just be 143,000,000m/1024pixels and got 139648.44

2. Relevant equations

already kinda put the equations i used

3. The attempt at a solution
just really wanted to make sure i was doing it all right

Last edited by a moderator: May 4, 2017