- #1
James889
- 192
- 1
Hi,
I have the first order differential equation [tex]y+y' = x[/tex]
y(0) = 0
First i tried to assume a solution of the form Ax+b, that didn't quite work.
Then i tried to use the Integrating factor technique, work follows
[tex]e^{\int1} = e^x[/tex]
[tex]\int e^x(y+y') = \int{xe^x}[/tex]
[tex] ye^x = \int xe^x[/tex]
let u = x, du=1
v = e^x dv=e^x
So i end up with:
[tex] ye^x = xe^x -e^x[/tex]
which is wrong...
Any ideas?
I have the first order differential equation [tex]y+y' = x[/tex]
y(0) = 0
First i tried to assume a solution of the form Ax+b, that didn't quite work.
Then i tried to use the Integrating factor technique, work follows
[tex]e^{\int1} = e^x[/tex]
[tex]\int e^x(y+y') = \int{xe^x}[/tex]
[tex] ye^x = \int xe^x[/tex]
let u = x, du=1
v = e^x dv=e^x
So i end up with:
[tex] ye^x = xe^x -e^x[/tex]
which is wrong...
Any ideas?