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A Force Question

  • #1

Homework Statement


A force F=-4.3i+2.0j+1.5k Newtons exerts a displacement of d=-0.8i+1.8j+-3.6k metres upon a small (ie mass is negligible) object. If the friction force is equal to Ffr=-0.2,, then what is the net work done upon the object?


Homework Equations





The Attempt at a Solution


I know the net work is the sum of all the individual work and the work equation is W=F.D. So i tried to work out the work of the initial force stated by multiplying the force and displacement stated which i got 1.64J. I think the only other work is caused by the friction force but when i try to work that out (because the mass is negligable) i get 0. Can someone please help?
 

Answers and Replies

  • #2
737
0
Mass is negligible only affects calculating the friction force using [itex]\mu N[/itex], but you already have the friction force. What can you do with it?
 
  • #3
could i put it as the force in the work equation and put the distance as the displacement thats stated in the question?
 
  • #4
Yes.
 
  • #5
so i have 1.64 from the first force i worked out and if i put the friction force into the work equation w= -0.2 x D i get -0.82. If I add the two works i have i get 0.82, but the answer is 1.3.... can you give me hints on what ive done wrong??
 
  • #6
737
0
I get that also. From where did you get this problem?
 

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