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This is equation I need to find solutions for

d^{2}u/d^{2}x + 1/2Lu = 0 where L(x)

I understand we can remove fraction from second term.

2 [d^{2}u/d^{2}x ] + Lu = 0

now how do I find solution of this equation ?

How do we deal with L ? because usually we have Y'(dy/dx or in this case du/dx ) or Y (in this case u) in second term in an ode.

Thanks.

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# B A function in an ode.

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