- #1
knockout_artist
- 70
- 2
Member advised to post homework-like problems in the homework sections
Hi,
This is equation I need to find solutions for
d2u/d2x + 1/2Lu = 0 where L(x)
I understand we can remove fraction from second term.
2 [d2 u/d2x ] + Lu = 0
now how do I find solution of this equation ?
How do we deal with L ? because usually we have Y'(dy/dx or in this case du/dx ) or Y (in this case u) in second term in an ode.
Thanks.
This is equation I need to find solutions for
d2u/d2x + 1/2Lu = 0 where L(x)
I understand we can remove fraction from second term.
2 [d2 u/d2x ] + Lu = 0
now how do I find solution of this equation ?
How do we deal with L ? because usually we have Y'(dy/dx or in this case du/dx ) or Y (in this case u) in second term in an ode.
Thanks.