Graph Problem: (n+1) Knots & Edges - How Many Possible Graphs?

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In summary, the conversation discusses the number of possible graphs that can be formed with (n+1) knots, without containing any loops. It is noted that the number of combinations without repetition is double the number of graphs with the same structure. The conversation also mentions the use of graph theory and the Pólya enumeration theorem in finding the final answer.
  • #1
pixel01
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Hello all,

I have got this graph problem. There are (n+1) knots which are numbered as A1, A2...An,An+1. We can connect those knots with lines (edges). The question is : How many possible graphs are there totally?
Notes: A graph can be a tree of any kinds, but muts not contain a loop.

Thanks
 
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  • #3
EnumaElish said:

Thanks for your ansser.
The number of combinations out of n elements,without repetition is just double the number of graphs of the same type. For n relatively large, we can have graphs without tree, and graphs with tree structure as well, so the final answer must be higher than just the number of combinations out of n elements...
 
  • #5
Thanks Enuma. I have done it!
Great chance to revise the graph theory.
 

1. What is a graph problem?

A graph problem involves finding the number of possible graphs that can be created with a given number of knots and edges.

2. What are knots and edges in a graph?

Knots, also known as vertices, are the points or nodes in a graph. Edges are the lines or connections between the knots.

3. What is the formula for calculating the number of possible graphs?

The formula for calculating the number of possible graphs is n^m, where n represents the number of knots and m represents the number of edges.

4. Can a graph have more edges than knots?

No, a graph cannot have more edges than knots. In fact, the maximum number of edges in a graph with n knots is n(n-1)/2.

5. Are all possible graphs unique?

No, not all possible graphs are unique. Some graphs may have the same number of knots and edges, resulting in duplicate graphs.

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