Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Classical Physics
Quantum Physics
Quantum Interpretations
Special and General Relativity
Atomic and Condensed Matter
Nuclear and Particle Physics
Beyond the Standard Model
Cosmology
Astronomy and Astrophysics
Other Physics Topics
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Classical Physics
Quantum Physics
Quantum Interpretations
Special and General Relativity
Atomic and Condensed Matter
Nuclear and Particle Physics
Beyond the Standard Model
Cosmology
Astronomy and Astrophysics
Other Physics Topics
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Physics
Classical Physics
A gravity conundrum involving a solid cylinder
Reply to thread
Message
[QUOTE="Baluncore, post: 6637086, member: 447632"] The nearby mass is a point on axis at the end of the cylinder. Consider the two ends of the cylinder are spheres, at centre of mass. The near end is at r = k/2; with mass M/2. The far end is at r = 3k/2; with mass M/2. The force due to the near end is; F = Gm(M/2) / ( k² / 4 ) = 2GmM / k² The force due to the far end is; F = Gm(M/2) / ( 9k² / 4 ) = 2GmM / 9k² When you add the two ends you get an increase. [/QUOTE]
Insert quotes…
Post reply
Forums
Physics
Classical Physics
A gravity conundrum involving a solid cylinder
Back
Top